0=18x^2-2x

Solution for 0=18x^2-2x equation:

0=18x^2-2x

We move all terms to the left:

0-(18x^2-2x)=0

We add all the numbers together, and all the variables

-(18x^2-2x)=0

We get rid of parentheses

-18x^2+2x=0

a = -18; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-18)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-18}=\frac{-4}{-36}
=1/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-18}=\frac{0}{-36}
=0
$